1^2+2(m-1)+(m+5)=0

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Solution for 1^2+2(m-1)+(m+5)=0 equation: 



1^2+2(m-1)+(m+5)=0

We add all the numbers together, and all the variables

2(m-1)+(m+5)+1=0

We multiply parentheses

2m+(m+5)-2+1=0

We get rid of parentheses

2m+m+5-2+1=0

We add all the numbers together, and all the variables

3m+4=0

We move all terms containing m to the left, all other terms to the right

3m=-4

m=-4/3

m=-1+1/3

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